Use these Geometry practice questions to review triangle rules, circles, perimeter, area, polygons, parallelograms, and the Pythagorean theorem. After answering each question, open the explanation to see the step-by-step solution.
Geometry Topics Covered
- Special right triangles
- Circle area and circumference
- Perimeter of composite figures
- Triangle angle sums
- Polygon interior angles
- Triangle area
- Parallelogram angle relationships
- The Pythagorean theorem
Sample Questions
- A. 2
- B. 3
- C. 3√2
- D. 3√3
- E. 6√2
Show Answer
In a 30-60-90 triangle, the side lengths follow this ratio:
1 : √3 : 2
The hypotenuse is the longest side and corresponds to 2 in the ratio. Since the hypotenuse is 6, the shortest side is half of 6.
6 ÷ 2 = 3
Therefore, the shortest side is 3.
- A. 8π
- B. 16π
- C. 64π
- D. 128π
- E. 256π
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The area of a circle is:
A = πr2
The diameter is 16, so the radius is half of 16.
r = 8
Substitute 8 for the radius:
A = π(8)2
A = 64π

- A. 27
- B. 33
- C. 36
- D. 42
- E. 48
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To find the perimeter, add the lengths of all the outside sides.
The missing vertical side is 6, because the full right side is 9 and the left vertical side is 3.
9 − 3 = 6
The missing horizontal side is 9, because the full top side is 12 and the bottom horizontal side is 3.
12 − 3 = 9
Now add the side lengths:
12 + 9 + 3 + 6 + 9 + 3 = 42
The perimeter is 42.

- A. 35°
- B. 40°
- C. 45°
- D. 50°
- E. 55°
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The angles inside a triangle add to 180°.
180° − 95° − 35° = 50°
The missing angle is 50°.
- A. 15π
- B. 225π
- C. 400π
- D. 900π
- E. 3000π
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The circumference of a circle is:
C = 2πr
The circumference is 30π, so substitute 30π for C.
30π = 2πr
Divide both sides by 2π:
r = 15
Now use the area formula:
A = πr2
A = π(15)2
A = 225π
- A. 540°
- B. 720°
- C. 810°
- D. 1080°
- E. 1440°
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The sum of the interior angles of a polygon is:
(n − 2) × 180°
A hexagon has 6 sides, so substitute 6 for n.
(6 − 2) × 180° = 4 × 180° = 720°
The sum of the interior angles is 720°.

- A. 20
- B. 30
- C. 35
- D. 40
- E. 80
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The area of a triangle is:
A =
1
2
bh
The base is 8 and the height is 5.
A =
1
2
(8)(5)
A = 20

- A. 9
- B. 10
- C. 20
- D. 22
- E. 24
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Adjacent angles in a parallelogram are supplementary, which means they add to 180°.
(4x + 12) + (3x + 14) = 180
7x + 26 = 180
7x = 154
x = 22
- A. 3, 13, and 14
- B. 4, 5, and 6
- C. 4, 9, and 10
- D. 5, 10, and 15
- E. 5, 12, and 13
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For three lengths to form a right triangle, the square of the longest side must equal the sum of the squares of the other two sides:
a2 + b2 = c2
For 5, 12, and 13:
52 + 122 = 132
25 + 144 = 169
169 = 169
Since the equation is true, 5, 12, and 13 can be the side lengths of a right triangle.

- A. 12
- B. 18
- C. 36
- D. 9√3
- E. 18√3
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An equilateral triangle can be split into two 30-60-90 triangles by drawing a height from the top vertex to the base.
The original side length is 6, so each half of the base is 3.
In a 30-60-90 triangle, the side lengths follow this ratio:
1 : √3 : 2
So the height of the equilateral triangle is 3√3.
Now use the triangle area formula:
A =
1
2
bh
A =
1
2
(6)(3√3)
A = 9√3
How to Use These Geometry Practice Questions
Start by answering each question before opening the explanation. Then compare your work to the step-by-step solution. If you miss a question, review the related geometry rule or formula before moving on.
For extra review, focus on the topics you miss most often. Geometry questions often depend on recognizing the correct formula or relationship, such as triangle angle sums, circle formulas, parallelogram angle rules, or the Pythagorean theorem.